Abstract:
To solve the problem of mechanism of potassium preparation with K-feldspar and phosphogysum, with K-feldspar, calcium sulfate and calcium oxide as raw materials, the thermal response process of system was analyzed under the different molar ratios (
n (K-feldspar) ∶
n (CaSO
4·2H
2O) ∶
n (CaO) = 1∶ 1∶ (2 ~ 16) ) . The experiments show that the most suitable proportion of material is 1∶ 1∶ 10, under the batching system, there are three kinds of calcium silicate in the calcined products, including CS, C
2S and C
3S, and their composition and proportion are associated with the reaction temperature of system. Besides, there is only one form (C
2AS) of sialic acid calcium salt, C
3A is nonexistent. These are inconsistent with the reported. There are two different reactions to displace generated K
2O, when the temperature is below 1 100 ℃, the replacement reaction occurs between KAl Si
3O
8 and CaO, and when the temperature is higher than 1 100 ℃, CaO would react with KAl Si
3O
8 and KAl Si
2O
6 respectively. Furthermore, when the temperature is below 1 200 ℃, K
2O is not combined with sulfate radical to sulfate, but escaping as gas. When the temperature is higher than 1 200 ℃, soluble potassium exists as K
2S
2O
8, and K
2SO
4 is unfound. TG-DSC experimental results show that theinitial displacement reaction temperature of the system is about 1 000 ℃, and the reaction goes into overdrive when the temperature is higher than 1 100 ℃. The results are consistent with the XRD analysis of the product which calcined at different temperatures. The cause of system weight loss at high temperature is that K
2SO
4 is converted into K
2S
2O
8 by releasing gaseous K
2O.